Question

Me ajudem nessa questão :
8(×+3)! = 2
(×+4)!

Answer 1

Hey!

$8(x+3)!=2(x+4)!\\\\\frac{8(x+3)!}{(x+4)!}=2\\\\\frac{8(x+3)!}{(x+4).(x+3)!}=2\\\\\frac{8}{(x+4)}.\frac{(x+3)!}{(x+3)!}=2\\\\\frac{8}{(x+4)}=2\\\\8=2(x+4)\\\\8=2x+8\\\\2x=8-8\\\\ 2x=0\\\\ x=0$