Question

Me ajudem nessa questao'?

Answer 1

Utilize a fórmula de Bháskara:
$X = \frac{-b+- \sqrt{b^2-4ac(delta)} }{2a}$

a) $16x^2-8x+1=0$
Δ = (- 8)² - 4 . 16 . 1           
Δ = 64 - 64
Δ = 0

$X = \frac{- (-8)+- \sqrt{0} } {2.16} = \frac{8}{32}$ ou (÷8) = $\frac{1}{4}$

S = {$\frac{1}{4}$}

b) $4x^2-4x-35=0$
Δ = (- 4)² - 4 . 4 . (- 35)
Δ = 16 + 560
Δ = 576

$X = \frac{- (-4)+- \sqrt{576} }{2.4} = \frac{4+-24}{8}$

x' = $\frac{4+24}{8} = \frac{28}{8} = 3,5$ ou (÷ 4) = $\frac{7}{2}$                 x" = $\frac{4-24}{8} = \frac{-20}{8} = 2,5$ ou (÷4) = $\frac{- 5}{2}$

S = {$\frac{7}{2} , \frac{-5}{2}$}