Question

me ajudem com esses triângulos

Answer 1

Resposta:

Explicação passo-a-passo:

d) sen 30 = cat. oposto/ hip

1/2 = 20/y

y = 2.20

y = 40

cos 30 = cat adj/ hip

cos 30 = x/y

√3/2 = x/40

40√3/2 = x

x = 20√3

E)

Sen 45 = x/10√2

√2/2 = x/10√2

10√2.√2/2 = x

10.2/2 = x

10 = x

x = 10

cos 45 = y/10√2

√2/2 = y/10√2

10√2.√2/2 = y

10.2/2 = y

y = 10

F)

Tg 45 = 8/x

1 = 8/x

x = 8

Tg 30 = 8/(x+ y)

sen 30/cos 30 = 8/(8 + y)

1/2 : √3/2 = 8/(8+y)

1/2 . 2/√3 = 8/(8+y)

2/2 . 1/√3 = 8/(8+y)

1/√3 . √3/√3 = 8/(8+y)

√3/3 = 8/(8+y)

√3.(8+y) = 24

8 + y = 24/√3

8 + y = 24/√3 .√3/√3

8+y = 24√3/3

8+y= 8√3

Y = 8√3 - 8

y = 8.(√3 - 1)