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Boa tarde Dayana!
Solução!
Para calcular o determinante de uma mtatriz quadrada de 2x2 basta multiplicar suas diagonais.
![A=\begin{vmatrix}
2 & 3 \\
1 & -2 \\
\end{vmatrix}\\\\\\\
Det_{A}=(2\times -2)-(3\times1)\\\\\
Det_{A}=(-4)-(3)\\\\\
Det_{A}=-7 \\\\\\\\\\
\boxed{Resposta:Det_{A}=-7}](https://tex.z-dn.net/?f=A%3D%5Cbegin%7Bvmatrix%7D+%0A++2+%26amp%3B+3+%5C%5C+%0A++1+%26amp%3B+-2+%5C%5C%0A++%5Cend%7Bvmatrix%7D%5C%5C%5C%5C%5C%5C%5C%0ADet_%7BA%7D%3D%282%5Ctimes+-2%29-%283%5Ctimes1%29%5C%5C%5C%5C%5C%0ADet_%7BA%7D%3D%28-4%29-%283%29%5C%5C%5C%5C%5C%0A+Det_%7BA%7D%3D-7+%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BResposta%3ADet_%7BA%7D%3D-7%7D "A=\begin{vmatrix}
2 & 3 \\
1 & -2 \\
\end{vmatrix}\\\\\\\
Det_{A}=(2\times -2)-(3\times1)\\\\\
Det_{A}=(-4)-(3)\\\\\
Det_{A}=-7 \\\\\\\\\\
\boxed{Resposta:Det_{A}=-7}")
Para calcular o determinante de uma matriz 3x3 tem que repetir as duas primeiras colunas e multiplicar suas diagonais..
![B=\left[\begin{array}{ccc}-1&0&1\\3&2&1\\4&3&5\end{array}\right] \\\\\\\ Det_{B}= \left[\begin{array}{ccccc}-1&0&1&-1&0\\3&2&1&3&2\\4&3&5&4&3\end{array}\right] \\\\\\\ Det_{B}= (-10+0+9)-(8-3+0)\\\\\ Det_{B}= (-1)-(5)\\\\\ Det_{B}=-6\\\\\\\\\
\boxed{Resposta:Det_{B}=-6}](https://tex.z-dn.net/?f=B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%26amp%3B0%26amp%3B1%5C%5C3%26amp%3B2%26amp%3B1%5C%5C4%26amp%3B3%26amp%3B5%5Cend%7Barray%7D%5Cright%5D+%5C%5C%5C%5C%5C%5C%5C+Det_%7BB%7D%3D+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccccc%7D-1%26amp%3B0%26amp%3B1%26amp%3B-1%26amp%3B0%5C%5C3%26amp%3B2%26amp%3B1%26amp%3B3%26amp%3B2%5C%5C4%26amp%3B3%26amp%3B5%26amp%3B4%26amp%3B3%5Cend%7Barray%7D%5Cright%5D+%5C%5C%5C%5C%5C%5C%5C+Det_%7BB%7D%3D+%28-10%2B0%2B9%29-%288-3%2B0%29%5C%5C%5C%5C%5C+Det_%7BB%7D%3D+%28-1%29-%285%29%5C%5C%5C%5C%5C+Det_%7BB%7D%3D-6%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BResposta%3ADet_%7BB%7D%3D-6%7D%0A "B=\left[\begin{array}{ccc}-1&0&1\\3&2&1\\4&3&5\end{array}\right] \\\\\\\ Det_{B}= \left[\begin{array}{ccccc}-1&0&1&-1&0\\3&2&1&3&2\\4&3&5&4&3\end{array}\right] \\\\\\\ Det_{B}= (-10+0+9)-(8-3+0)\\\\\ Det_{B}= (-1)-(5)\\\\\ Det_{B}=-6\\\\\\\\\
\boxed{Resposta:Det_{B}=-6}")
![Det_{A} \times Det_{B}\\\\\\
-7\times -6=42\\\\\
\boxed{Resposta:Det_{A} \times Det_{B}=42}](https://tex.z-dn.net/?f=Det_%7BA%7D+%5Ctimes+Det_%7BB%7D%5C%5C%5C%5C%5C%5C%0A-7%5Ctimes+-6%3D42%5C%5C%5C%5C%5C%0A%5Cboxed%7BResposta%3ADet_%7BA%7D+%5Ctimes+Det_%7BB%7D%3D42%7D "Det_{A} \times Det_{B}\\\\\\
-7\times -6=42\\\\\
\boxed{Resposta:Det_{A} \times Det_{B}=42}")
Boa tarde!
Bons estudos!
Solução!
Para calcular o determinante de uma mtatriz quadrada de 2x2 basta multiplicar suas diagonais.
Para calcular o determinante de uma matriz 3x3 tem que repetir as duas primeiras colunas e multiplicar suas diagonais..
Boa tarde!
Bons estudos!
dayanapeixoto501:
Boa tarde! Muuuito obrigada!
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