Matemática, perguntado por rodriguezvictor, 6 meses atrás

Me ajudem b) (2x-3)×2=25
C) (x+1)×2-x=7
D(x-1)×2=x+5
E)(1-x)×2-3x=1
F)(3x-2)×2=(2-x)×2
G)(2x-1)×2=(x+5)×2
H)(x-2)×2+(x+1)×2=5

Soluções para a tarefa

Respondido por arielsilva1512
1

Resposta:

b) (2x-3)×2=25

4x - 6 = 25 \\ 4x = 25 + 6 \\ 4x = 31 \\ x =  \frac{31}{4}

C) (x+1)×2-x=7

2x + 2 - x = 7 \\ x + 2 - 7 = 0 \\ x - 5 = 0 \\ x = 5

D(x-1)×2=x+5

2x - 2 = x + 5 \\ 2x - 2 - x - 5 = 0 \\ x - 7 = 0 \\ x = 7

E)(1-x)×2-3x=1

2 - 2x - 3x = 1 \\ - 5x = 1 - 2 \\  - 5x =  - 1  \times ( - 1) \\ 5x = 1 \\ x =  \frac{1}{5}

F)(3x-2)×2=(2-x)×2

6x - 4 = 4 - 2x \\ 6x - 4 + 2x = 4 \\ 8x = 4 + 4 \\ 8x = 8 \div 8 \\ x = 1

G)(2x-1)×2=(x+5)×2

4x - 2 = 2x + 10 \\ 4x - 2 - 2x = 10 \\ 2x = 10 + 2 \\ 2x = 12 \div 2 \\ x = 6

H)(x-2)×2+(x+1)×2=5

2x - 4  + 2x + 2 = 5 \\ 4x - 2 = 5 \\ 4x = 5 + 2 \\ 4x = 7 \\ \\  x =  \frac{7}{4}

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