Question

me AJUDEM ai pessoal, o exercício está no anexo.

Answer 1

$2^{3x+6}+2^{3x+5}+2^{3x+4}+2^{3x+3}+2^{3x+2}+2^{3x+1}=64512\\\\2^{3x}*(2^6+2^5+2^4+2^3+2^2+2^1) = 64512\\\\2^{3x}= \frac{64512}{126} \\\\2^{3x}=512$


fatorando o 512

512 |2
256 |2
128 | 2
 64  | 2
 32 | 2
16 | 2
8 | 2 
4 | 2
2 | 2 
1 

512 = 2^9


$2^{3x}=2^9\\\\3x=9\\x=3$