Question

Me ajudem a resolver, fórmula de bhaskaras

x^2-x = x -1

Answer 1

${x}^{2} - x = x - 1$
${x}^{2} - x - x + 1 = 0$
${x}^{2} - 2x + 1 = 0$
$x = \frac{ - ( - 2) + - \sqrt{ {( - 2)}^{2} - 4 \times 1 \times 1} }{2 \times 1}$
$x = \frac{2 + - \sqrt{4 - 4} }{2}$
$x = \frac{2 + - \sqrt{0} }{2}$
$x = \frac{2 + - 0}{2}$
$x = \frac{2}{2}$
$x = 1$