Question

Me ajudem a resolver essas contas preciso entrega amanhã por favor
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Answer 1

Resposta:

a) 2+5x⋅8+(2)^2⋅(2)^2=

=(40x+2)+(2)^2⋅(2)^2=

=(40x+2)+16=

R= 40x+18

b) 5+4x⋅25−6^2+3:(−3)1=

=(100x+5)−36+3:(−3)=

=(100x−31)+3:(−3)=

=(100x−31)±(3⋅1/3)=

=(100x−31)+(−1)=

R= 100x−32

c) 7x⋅4+5−1+12:(+2)+27=

=(28x+5)−1+(6⋅2)⋅1/2+27=

=(28x+4)+6+27=

=(28x+10)+27=

R= 28x+37

d) =5−1⋅1+6x⋅4+6+49=

=5−1+24x+6+49=

=(24x+4)+6+49=

=(24x+10)+49=

R= 24x+59

e) =8+(5)^2:(−5)+9x+1=

=8+(−5)2⋅−15+9x+1=

=8+(−5)+9x+1=

=(9x+3)+1=

R= 9x+4

f) 3+4:(−4)+9x⋅(3)^2+5=

=3±(4⋅1/4)+9x⋅9+5=

=3+(−1)+81x+5=

=(81x+2)+5=

R= 81x+7

g) =8:(2)^3+4x⋅1+9+2=

=(2)^3⋅(1-2)^3+4x+9+2=

=(4x+1)+9+2=

=(4x+10)+2=

R= 4x+12

marca como melhor resposta prfv

Espero ter ajudado!!