Question

Me ajudem a resolver essa

Answer 1

Vejamos:

5^x² ≤ (0,2)-¹

5^x² ≤ (2/10)-¹

5^x² ≤ (10/2)¹

5^x² ≤ 5¹

x² ≤ 1
x≤ √1
x ≤ +/- 1
s = {x∈R/-1≤x1}