Question

Me ajudem a calcular as seguintes potencias

(3/7) elevado a -2
(2/5) elevado a -1
(1/3) elevado a -3
(-2/5) elevado a -3
(-2/3) eleavado a -4

Answer 1

$( \frac{3}{7})^{-2} = (\frac{7}{3})^{2} = \frac{7}{3} * \frac{7}{3} = \frac{49}{9}$

$( \frac{2}{5} )^{-1} = (\frac{5}{2})^{1} = \frac{5}{2}$

$( \frac{1}{3} )^{-3} = 3^{3} =3*3*3=27$

$( \frac{-2}{5} )^{-3} = (\frac{-5}{2} )^{3} = \frac{-125}{8}$

$( \frac{-2}{3} )^{-4} =( \frac{-3}{2} )^{4} = \frac{81}{16}$

Answer 2

Boa noite 

(3/7) elevado a -2  = (49/9)
(2/5) elevado a -1  = 5/2
(1/3) elevado a -3  = 27
(-2/5) elevado a -3 = -125/8
(-2/3) elevado a -4 = 81/16