Question

me ajude como resolver essa equaçao ! x²-8x+16=0

Answer 1

$x^{2} -8x+16=0\\\\a=1~;~b=-8~;~c=16\\\\\\ \Delta=b^2-4ac\to \Delta=(-8)^2-4.1.16\to \Delta=64-64\to \boxed{\Delta=0}\\\\ x'=x''\\\\\\ x= \dfrac{-b\pm \sqrt{\Delta} }{2a} \to~~ x= \dfrac{-(-8)\pm \sqrt{0} }{2.1} \to~~ x= \dfrac{8\pm 0}{2} \to~~\\\\\\ x'=x''= \dfrac{8}{2} \to~~ \boxed{x'=x''= 4}\\\\\\\\\\ \Large\boxed{\boxed{S=\{ 4\}}}$

Answer 2

x² - 8x + 16 = 0
a = 1; b = - 8; c = 16

Δ = b² - 4ac
Δ = (-8)² - 4.1.16
Δ = 64 - 64
Δ = 0

x = - b +/- √Δ  = - ( - 8)
          2a             2.1

x = 8/2 = 4

Resp.: x = 4