Question

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Answer 1

$a = {75}^{o}$

(ângulos opostos pelo vértice)

$2c = {100}^{o} \\ c = {50}^{o}$

(ângulos opostos pelo vértice)

$5b + {75}^{o} = {180}^{o} \\ 5b = {180}^{o} - {75}^{o} \\ 5b = {105}^{o} \\ b = \frac{ {105}^{o} }{5} \\ b = {21}^{o}$

(ângulos suplementares)

$5d + {100}^{o} = {180}^{o} \\ 5d = {80}^{o} \\ d = \frac{ {80}^{o} }{5} \\ d = {16}^{o}$

(ângulos suplementares)