Question

me ajudaaaaaaaaa [-10+2³(-2)²] bbbbbbbbbbbbbbb[$\sqrt{x} \sqrt{x} \sqrt{x}$

Answer 1

Resposta:

Explicação passo a passo:

$\left[-10+2^3\left(-2\right)^2\right]\\-10+8\left(-2\right)^2\\-10+8\cdot \:4\\-10+32\\22$