Question

me ajuda pfvr preciso pra hoje​

Answer 1

Explicação passo-a-passo:

2)

$\boldsymbol{f(x) = {x}^{2} - 6x + 8 } \\ \boldsymbol{0 = {x}^{2} - 6x + 8 } \\ \boldsymbol{ {x}^{2} - 6x + 8 = 0} \\ \boldsymbol{ {x}^{2} - 2x - 4x + 8 = 0 } \\ \boldsymbol{x(x - 2) - 4(x - 2) = 0} \\ \boldsymbol{(x - 2) \times (x - 4) = 0} \\ \boldsymbol{x - 2 = 0} \\ \boldsymbol{x - 4 = 0} \\ \boxed{ \boldsymbol{x = 2} } \\ \boxed{ \boldsymbol{x = 4} }$

R: ITEM (B)

3)

$\boldsymbol{f(x) = {x}^{2} - 6x + 9} \\ \boldsymbol{0 = {x}^{2} - 6x + 9} \\ \boldsymbol{0 - {x}^{2} + 6x - 9 = 0} \\ \boldsymbol{ - {x}^{2} + 6x - 9 = 0} \\ \boldsymbol{ - {x}^{2} + 3x + 3x - 9 = 0} \\ \boldsymbol{ - x(x - 3) + 3(x - 3) = 0} \\ \boldsymbol{ - (x - 3) \times (x - 3) = 0} \\ \boldsymbol{ { - (x - 3)}^{1} \times {(x - 3)}^{1} = 0 } \\ \boldsymbol{ { - (x - 3)}^{1 + 1} = 0} \\ \boldsymbol{ { - (x - 3)}^{2} = 0 } \\ \boldsymbol{ {(x - 3) }^{2} = 0} \\ \boldsymbol{x - 3 = 0} \\ \boxed{ \boldsymbol{x = 3} }$

R: ITEM (A)

Answer 2

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