Question

Me ajuda pfv
-x2 -4 x + 12 = 0

Answer 1

-x² -4x +12 = 0

a: -1

b: -4

c: 12

Δ = b² - 4.a.c

Δ = (-4)² -4.(-1).12

Δ = 16 + 48

Δ = 64

x = -b±√Δ/2.a

x = 4±√64/2.(-1)

x = 4±8/-2

x' = 4+8/-2

x' = 12/-2

x' = -6

x'' = 4-8/-2

x'' = -4/-2

x'' = 2