Question

me ajuda pfv 25 pontos...

Answer 1

a) [(-4)²]^3 = [(16)]³ = 4096 = (-4)^6

c) [(-3)³]² = [(-27)]² = 729 = (-3)^6

e) [(2)^4]^5 = [(16)]^5 = 1.048.576 = (2)^20

b) [(5)³]^4 = [(125)]^4 = 244.140.625 = 5^12

d) [(-7)³]^3 = [(-343)³] = -40.353.607 = (-7)^9

f) [(-7)^5]^3 = [(-16.807)]³ = -474.756.151 * 10^12 = (-7)^15

Answer 2

Propriedade de Potência: Quando a expressão é do tipo $[( -4)^{2} ]^{3}$, multiplica-se os expoentes e conserva-se a base⇒ $( -4)^{2*3}\to ( -4)^{6}$.


$a)[( -4)^{2} ]^{3} \to\\\\ ( -4)^{2*3}\to ( -4)^{6}\to +4.096$



$b)[( +5)^{3} ]^{4} \to\\\\ (+5)^{3*4} \to (+5)^{12} \to +244.140.625$



$c)[( -3)^{3} ]^{2} \to\\\\ ( -3)^{3*2}\to ( -3)^{6}\to +729$



$d)[( -7)^{3} ]^{3} \to\\\\ ( -7)^{3*3}\to ( -7)^{9}\to -40.353.607$



$e)[( +2)^{4} ]^{5} \to\\\\ ( +2)^{4*5}\to ( +2)^{20}\to +1.048.576$



$f)[( -7)^{5} ]^{3} \to\\\\ ( -7)^{5*3}\to ( -7)^{15}\to -4.747.561.509.943$