Question

me ajuda gnt 
sabendo que log5 2=0,43 e log5 3=0,68 calcule:
a)log5 18 b) log2 9

Answer 1

a)

$\log_518=\\\\\log_5(2\cdot3^2)=\\\\\log_52+\log_53^2=\\\\\log_52+2\cdot\log_53=\\\\0,43+2\cdot0,68=\\\\0,43+1,36=\\\\\boxed{1,79}$


b) Passemos para a base 5;



$\log_29=\\\\\frac{\log_59}{\log_52}=\\\\\frac{\log_53^2}{\log_52}=\\\\\frac{2\cdot\log_53}{\log_52}=\\\\\frac{2\cdot0,68}{0,43}=\\\\\frac{1,36}{0,43}=\\\\\boxed{3,16}$