Question

Me ajuda gente
Encontre x' e x'' 3x²-7x+4=0 ​

Answer 1

Resposta:

$x_{1} =\frac{4}{3},\:x_{2} =1$

Explicação passo a passo:

$x_{1,\:2}=\frac{-\left(-7\right)\pm \sqrt{\left(-7\right)^2-4\cdot \:3\cdot \:4}}{2\cdot \:3}$

$x_1=\frac{-\left(-7\right)+1}{2\cdot \:3},\:x_2=\frac{-\left(-7\right)-1}{2\cdot \:3}$

$x_{1} =\frac{7+1}{2\cdot \:3}=\frac{4}{3}$

$x_{2}= \frac{7-1}{2\cdot \:3}=1$