Question

me ajuda aí pessoal pra amanhã, pelo método de cramer
x+2y+3z=14
4y+5z=23
6z=18

Answer 1

x + 2y + 3z = 14
4y + 5z = 23
6z = 18
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D

|.1 2 3| 1 2
|0 4 5| 0 4
|0 0 6| 0 0

24 + 0 = 24


Dx

|14. 2 3| 14 2
|23 4 5| 23 4
|18 0 6| 18 0

336 + 180 - 276 - 216 = 24

Dy

|..1 14 3|. 1 14
|0 23 5| 0 23
|.0 18 6| 0 18

138 - 90 = 48


Dz

|.1 2 14| 1 2
|0 4 23|0 4
|0 0 18| 0 0

72 + 0 = 72




x = DX/D
x = 24/24
x = 1

y = Dy/D
y = 48/24
y = 2

z = Dz/D
z = 72/24
z = 3


s={ 1, 2, 3 }