Question

Matrizes determinantes, após ver anexo: Determine o valor de E = (det D - det A) x (det B - det C)

Answer 1

Resolvendo os determinantes:
A =
$\frac{3}{4} \times - 1 - ( \frac{ - 1}{8} \times - 2) \\ \frac{ - 3}{4} - \frac{2}{8} = \\ \frac{ - 3}{4} - \frac{1}{4} = \frac{ - 4}{4} = - 1$
B =
$5 \times - 4 - ( - 6 \times 4) \\ - 20 + 24 = 4$
C=
$(0 \times 0 \times - 2 + 2 \times 6 \times 4+ 1 \times 0 \times 0) - (1 \times 0 \times 4 + 2 \times 0 \times - 2 + 0 \times 6 \times 0) \\ 0 + 48 + 0 - 0 = 48$
D=
$( \frac{2}{3} \times 2 \times 4 + \frac{1}{2} \times \frac{2}{5} \times 3 + 4 \times 2 \times 1 - (3 \times 2 \times 4 + 1 \times \frac{2}{5} \times \frac{2}{3} + 4 \times 2 \times \frac{1}{2} )) \\ ( \frac{16}{3} + \frac{6}{10} + 8 - (24 + \frac{4}{15} + \frac{8}{2} )) \\ ( \frac{16}{3} + \frac{3}{5} + 8 - (24 + \frac{4}{15} + 4)) \\ \frac{16}{3} + \frac{3}{5} + 8 - 24 - \frac{4}{15} - 4 \\ \frac{16}{3} + \frac{3}{5} - \frac{4}{15} - 20 \\ \frac{80 + 9 - 4 - 300}{15} \\ \frac{89 - 304}{15} \\ \frac{ - 215}{15}$
Logo:
$e = ( \frac{ - 215}{15} - ( - 1) \times (4 - 48)) \\ e = (( \frac{ - 215}{15} + 1) \times - 44 \\ e = ( \frac{ - 215 + 15}{15} \times - 44) \\ e = ( \frac{ - 200}{15} \times - 44) \\ e = \frac{8800}{15} \\ e = \frac{1760}{3} \\ e = 586.67$