Question

Matemática básica - Potenciação$(4^{3/3} + 8^{-2/2} - 2^{-2}) /0,75$

Answer 1

$4^{(\frac{3}{3}) } = 4^{1}$

$8^{\frac{-2}{2}} = 8^{-1} = 1/8$

$2^{-2}= \frac{1}{2^{2}} = \frac{1}{4}$

$0,75 = \frac{3}{4}$

4+1/8 -1/4 = 4-1/8 = 31/8

(31/8) / (3/4) = 31/6