Question

m²-12m+27=0 como resolvo essa equaçã?

Answer 1

Resposta:

Explicação passo-a-passo:

$m^{2} -12+27=0\\Δ= b^{2}-4.a.c\\Δ= (-12)^{2}-4.(1).(27)\\Δ=144-108\\Δ=36\\\\X=\frac{-b±\sqrt[]{Δ} }{2a}\\×=\frac{-(-12)±\sqrt[]{36} }{2.(1)}\\×=\frac{12±6}{2}=\left \{ {{x^{1} = \frac{12-6}{2} =\frac{6}{2} = 3} \atop {x^{2} = \frac{12+6}{2}=\frac{18}{2}=9 }} \right.$