Question

Logaritmos.
Me ajudem.

Answer 1

GO: requer conhecimento de potencias

1-$log _{36} \sqrt{6}=$

posso escrever tirando a raiz, assim 

$log_{36} 6^{ \frac{1}{2} } igual 6^{2x}= 6^{ \frac{1}{2} } 2x=1/2 x=1/4$

2-$Log_{10} 0,01 log_{10} 1 0^{-2} 10^{x}= 10^{-2} x=-2$

3-$log_{9} 1/27 3^{2x} = 1/ 3^{3} 2x= {-3} x= -3/2$

4-$log_{0,2} \sqrt[3]{25} log_{1/5} 5^{ \frac{3}{2} } 5^{-x}= 5^{ \frac{3}{2} }  x=-3/2$

5-$log_{125} 0,64 5^{3x}= 5/4^{-2} x= -2/3$

6-$log_{5/3} 3/5 3/5 x^{-x} = 3/5 x=-1$

7-$log_{1/4} 2^{ \frac{3}{2} } 2^{-2x}= 2 ^{3/2} x= -3/4$

8-$log_{10} 0,1 x= -1$