Question

logaritmo de 32 na base 0,5?

Answer 1

log(0,5)32 = x
(0,5)^x = 32
(1/2)^x = 32
(2-¹)^x = 2^5
-x = 5
x = -5

Answer 2

log   32  = x
    1/2
 (1/2)^x = 32
 
(1/2)^x = 2 ^5
2^-x = 2^5
-x =  5
x = - 5