Question

log2x+log2x^2+log2x^3=6 calcule x

Answer 1

$log_{2}x + log_{2} {x}^{2} + log_{2} {x}^{3} = 6 \\ \\ log_{2}x + 2log_{2}x + 3 log_{2}x = 6 \\ \\ 6 log_{2}x = 6 \\ \\ log_{2}x = 1 \\ \\ {2}^{1} = x \\ \\ x = 2$