Question

log²(x+3) + log²3 - log² (x-1) = 2 ?

Answer 1

$log_2(x+3)+log_23-log_2(x-1)=2\\\\log_2(\frac{3(x+3)}{x-1})=2 \\ \\(\frac{3(x+3)}{x-1})=2^2 \\ \\(\frac{3(x+3)}{x-1})=4 \\ \\ 3(x+3)=4(x-1) \\ \\ 3x+9=4x-4 \\ \\ 9+4=4x-3x \\ \\ 13=x \\ \\ \\ S=\{13\}$