Question

log2 () − log2 ( + 1) > log2(2 + 6)

Answer 1

Resposta:

$x > 8$

Explicação passo a passo:

$\log _2\left(x\right)-\log _2\left(1\right) > \log _2\left(2+6\right)$

$\log _2\left(x\right) > \log _2\left(2+6\right)+\log _2\left(1\right)$

$x > 2^{\log _2\left(2+6\right)+\log _2\left(1\right)}$

$x > 8$