Question

log2=0,30, log3=0,47 e log5=0,69 calcule: a)log4 b)log(2/5) c)log12 d) log(10/3) e) log20 f) log² 3 g) log30 h)log (15/10)

Answer 1

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Ola Prisemilly

log2 = 0.30
log3 = 0.47
log5 = 0.69
log10 = 1

a) log4 = log2² = 2log(2) = 0.60

b) log(2/5) = log2 - log5 = 0.30 - 0.69 = -0.39

c) log12 = log(2*2*3) = 2log2 + log3 = 0.60 + 0.47 = 1.07 

d) log(10/3) = log10 - log3 = 1 - 0.47 = 0.53 

e) log20 = log(2*2*5) = 2log2 + log5 = 0.60 + 0.69 = 1.29 

f) log²(3) = 0.47² = 0.2209

g) log30 = log(3*10) = log3 + log10 = 0.47 + 1 = 1.47

h) log(15/10) = log15 - log10 = log3 + log5 - log10 = 0.47 + 0.69 - 1 = 0.16

pronto