Question

log x na base 2 + 4 log 8 na base x = 8

Answer 1

$log_2x+4log_x8=8 \\ \\ log_2x+4.\frac{log_28}{log_2x}=8 \\ \\ log_2x=4.\frac{3}{log_2x}=8 \\ \\ log_2x=\frac{12}{log_2x}=8 \\ \\ \boxed{y=log_2x} \\ \\ y+\frac{12}{y}=8y \\ \\ y^2+12-8y=0 \\ \\ y_1=2 \ e \ y_2=6$
$\boxed{log_2x=2\rightarrow x=4} \\ \\ \boxed{log_2x=6\rightarrow x=64}$