Question

log(2) x + log(2^1/2) x = -3

Answer 1

$log_2x+log_{\sqrt{2}}x=-3 \\ \\ log_2x+\frac{log_2x}{log_2\sqrt{2}}=-3 \\ \\ log_2x+\frac{log_2x}{\frac{1}{2}}=-3 \\ \\ log_2x+2log_2x=-3 \\ \\ 3log_2x=-3 \\ \\ log_2x=-1 \\ \\ x=2^{-1} \\ \\ x=\frac{1}{2}$