Question

log(-x elevado 2 +6x)=3​

Answer 1

Resposta:

$log(x {}^{2} + 6x) = 3 \\ x {}^{2} + 6x = 10 { }^{3} \\ x {}^{2} + 6x = 1000 \\ x {}^{2} + 6x - 1000 = 0 \\ x = \frac{ - b + - \sqrt{b {}^{2} - 4ac } }{2a} \\ x = \frac{ - (6) {}^{2} + - \sqrt{6 {}^{2} - 4 \times 1 \times - 1000 } }{2 \times 1} \\ x = \frac{ - 36 + - \sqrt{36 + 4000} }{2} \\ x = \frac{ - 36 + - \sqrt{4036} }{2} \\ x = \frac{ - 36 + - 2 \sqrt{1009} }{2} \\ x = \frac{ - 36 + 2 \sqrt{1009} }{2} \\ x = - 18 + 2 \sqrt{1009 } \\ \\ x = - 18 - 2 \sqrt{1009}$