Question

log de 128 na base 32

Answer 1

Log 128 = x

32

128 = 32^x

2^7 = ( 2^5)^x

2^7 = 2^ 5x

7 = 5x

5x = 7

x = 7/5

Answer 2

$log_{32}(128 ) = x \\ \\ {32}^{ x } = {128} \\ \\ {2}^{5x} = {2}^{7} \\ \\ 5x = 7 \\ \\ x = \frac{7}{5}$
espero ter ajudado!

bom dia !