Question

Log de 125 na base 1/3 = x
Ajudem - me ;s 

Answer 1

Olá, Jade.

$\log_{\frac13}125 = \\\\ =\frac{\log_3125}{\log_3\frac13}= \\\\ =\frac{\log_35^3}{\log_33^{-1}}= \\\\ =\frac{3\log_35}{-1}= \\\\ =-3\log_35=$

$=\boxed{-3\frac{\log5}{\log3}}$