Question

log 8 na base 1/2 ??

Answer 1

$log_{\frac{1}{2}}8 = x \\\\ (\frac{1}{2})^{x} = 8 \\\\ (2^{-1})^{x} = (2)^{3} \\\\ (2)^{-x} = (2)^{3} \\\\ (\not{2})^{-x} = (\not{2})^{3} \\\\ -x = 3 \ \ \times -1 \\\\ \boxed{x = -3} \\\\\\ \therefore \boxed{\boxed{log_{\frac{1}{2}}8 = -3}}$

Answer 2

Stephani pra resolver é só você lembrar das propriedades de log


log 8 = x
 1/2

(1/2)^x=8  → Simplifica

(2^{-1})^x=2^3

-x=3
x=-3