Question

Log 8 +log 35 +log12

Answer 1

$log8+log35+log12=log8*35*12=log3360=3,5$

Answer 2

Lembre-se que, $\text{log}_b~a+\text{log}_b~c=\text{log}_b~(a\cdot c)$.

Assim, $\text{log}~8+\text{log}~35+\text{log}~12=\text{log}~(8\cdot35\cdot12)=\text{log}~3~360$.

Por outro lado, $\text{log}_b~a=x~~\Rightarrow~~b^{x}=a$.

Com isso, $\text{log}~3~360=x~~\Rightarrow~~10^{x}=3~360$.

E, obtemos $x\approx3,526~~\Rightarrow~~\text{log}~8+\text{log}~35+\text{log}~12\approx3,526$.