Question

log 75 - log 0,15 + log 2,4

Answer 1

$log_{10}(75) - log_{10}(0,15) + log_{10}(2,4) \\ log_{10}( \frac{75 \times2,4 }{0,15} ) \\ log_{10}(75 \times16) \\ log_{10}(1200) \\ log_{10}(100 \times12)$

Usando a expressão, temos:

$log_{a}(x.y) = log_{a}(x) + log_{a}(y) \\ log_{10}(100) + log_{10}(12) \\ log_{10}( {10}^{2} ) + log_{10}(12) \\ 2 + log_{10}(12)$