Question

log 32 na base 1/2 =x

Answer 1

$log_{ \frac{1}{2} }32= log_{ 2^{-1} } 2^{5}=-5log_{2}2=-5$

Answer 2

Boa Noite!

$log_ \frac{1}{2} 32=x \\ \\ (\frac{1}{2})^x=32 \\ \\ (2^{-1})^x=2^5 \\ \\ 2^{-x}=2^5 \\ \\ -x=5 \\ \\ x=-5$

Duvidas?! é só comentar