log 16 com base 1/2 heeelp
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Boa tarde!
![log_{ \frac{1}{2} }16\\\\\
log_{ \frac{1}{2} }16=x\\\\\
(\frac{1}{2})^{x} =16\\\\\\
(\frac{1}{2})^{x} =2 ^{4} \\\\\\
(\frac{1}{2})^{x} =( \frac{1}{2}) ^{-4} \\\\\\
\boxed{x=-4}](https://tex.z-dn.net/?f=log_%7B+%5Cfrac%7B1%7D%7B2%7D+%7D16%5C%5C%5C%5C%5C%0Alog_%7B+%5Cfrac%7B1%7D%7B2%7D+%7D16%3Dx%5C%5C%5C%5C%5C%0A+%28%5Cfrac%7B1%7D%7B2%7D%29%5E%7Bx%7D+%3D16%5C%5C%5C%5C%5C%5C%0A+%28%5Cfrac%7B1%7D%7B2%7D%29%5E%7Bx%7D+%3D2+%5E%7B4%7D+%5C%5C%5C%5C%5C%5C%0A+%28%5Cfrac%7B1%7D%7B2%7D%29%5E%7Bx%7D+%3D%28+%5Cfrac%7B1%7D%7B2%7D%29+%5E%7B-4%7D+%5C%5C%5C%5C%5C%5C%0A++%5Cboxed%7Bx%3D-4%7D "log_{ \frac{1}{2} }16\\\\\
log_{ \frac{1}{2} }16=x\\\\\
(\frac{1}{2})^{x} =16\\\\\\
(\frac{1}{2})^{x} =2 ^{4} \\\\\\
(\frac{1}{2})^{x} =( \frac{1}{2}) ^{-4} \\\\\\
\boxed{x=-4}")
Boa tarde!
Boa tarde!
Respondido por
6
Boa noite Caio
log1/2(16) = x
(1/2)^x = 16 = 2^4
2^-x = 4
x = -4
log1/2(16) = x
(1/2)^x = 16 = 2^4
2^-x = 4
x = -4
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