Question

log 1/64 na base 2 * log raiz de 8 na base 4

Answer 1

$\log_{2} \dfrac{1}{64} \times\log_{4} \sqrt{8} =$

$\log_{2} 2^{-6} \times\log_{4} \sqrt{ 2^{3} } =$

$-6.\log_{2} 2 \times\log_{4} 2^{ \frac{3}{2} } =$

$-6.1 \times\log_{4} 2^{ \frac{3}{2} } =$

$-6.\log_{4} 2^{ \frac{3}{2} } =$

$-6.\dfrac{3}{2}.\log_{4} 2 =$

$-3.3.\log_{4} 2 =$

$-9.\log_{4} 2 =$

$-9. \dfrac{\log_{2} 2}{\log_{2} 4} =$

$-9. \dfrac{1}{\log_{2} 2^{2} } =$

$-9. \dfrac{1}{2.\log_{2} 2} =$

$-9. \dfrac{1}{2.1} =$

$-9. \dfrac{1}{2} =$

$-\dfrac{9}{2}$