Question

log 1/4 na base (1/16)9

Answer 1

Logaritmo de 1 sobre 16 elevado a 9 na base 1 sobre 4:

$\log_{\frac{1}{4}} (\frac{1}{16})^9= \\ \\ =9\cdot\log_{\frac{1}{4}} (\frac{1}{4})^2=\\ \\ =9\cdot2=\\ \\ =18$