Question

limx 2 x²-x²-2x/x2-3x+2

Answer 1

Resposta:

$\lim_{x \to 2} \dfrac{x^{3}-x^{2}-2x}{x^{2}-3x+2}=\\\\\\=\lim_{x \to 2} \dfrac{x.(x+1).(x-2)}{(x-1).(x-2)}=\\\\\\=\lim_{x \to 2} \dfrac{x.(x+1).(x-2)}{(x-1).(x-2)}=\\\\\\=\lim_{x \to 2} \dfrac{x.(x+1)}{(x-1)}=\\\\\\=\dfrac{2.(2+1)}{(2-1)}=\dfrac{2.3}{1}=6$

Explicação passo-a-passo: