Question

Limite de x² - 16 / x² - 5x +4? com x tendendo a 4?

Answer 1

$\lim_{x \to 4} \frac{x^2-16}{x^2-5x+4}$


Aplica L'hopital

$\lim_{x \to 4} \frac{f'(x)}{g'(x)} \\ \\ \lim_{x \to 4} \frac{2x}{2x-5} = \frac{2.4}{2.4-5}= \boxed{\frac{8}{3}}$