Question

lim x²+2x-3 sobre 5-3x quando o x tende a -3

Answer 1

lim [x -> -3] (x² + 2x - 3)/(5 - 3x)

((-3)² + 2(-3) - 3)/(5 - 3(-3)) =
= (9 - 6 - 3)/(5 + 9) =
= 0/14 =
= 0

Portanto:

lim [x -> -3] (x² + 2x - 3)/(5 - 3x) = 0