Question

lim x-1/x^2-3x+2
x->1

Answer 1

$\\\lim_{x\rightarrow1}\frac{x-1}{x^2-3x+2}=\\\\\\\lim_{x\rightarrow1}\frac{x-1}{(x-1)(x-2)}=\\\\\\\lim_{x\rightarrow1}\frac{1}{x-2}=\\\\\\\frac{1}{1-2}=\\\\\boxed{-1}$