Question

lim t tendendo á-3 t³-4t+15/t²-t-12 na regra l´hospital

Answer 1

(t³-4t+15)/(t²-t-12)                  t--> -3
-27+12+15 / 9 +3 - 12    =0/0 , derivando:
(3t² -4) / (2t-1)           t -- > -3
(27 - 4) / (-7)=
 - 23/7 ≈ -3,28571