Question

(ITA-SP) Calcule o valor de log2 16 - log4 32

Answer 1

$Log 2^{16} - Log 4^{16} = \\ Log 2^{2^4} - Log 2^2^{(2^5)}=$

$4Log 2^{2} - 5Log 2^2^{(2)}=$

$4 \frac{Log2}{Log2} -5\frac{Log2}{Log2^2}=4 \frac{Log2}{Log2} -5\frac{Log2}{2Log2} = 4- \frac{5}{2}= \frac{3}{2}$

Answer 2

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{log_2\:16 - log_4\:32 = log_2\:2^4 - log_{2^2}\:{2^5}}$

$\mathsf{log_2\:16 - log_4\:32 = 4\:log_2\:2 - \dfrac{5}{2}\:.\:log_{2}\:{2}}$

$\mathsf{log_2\:16 - log_4\:32 = 4 - \dfrac{5}{2}}$

$\boxed{\boxed{\mathsf{log_2\:16 - log_4\:32 = \dfrac{3}{2}}}}$