Question

Interpole sete meios aritméticos entre -20 e 12

Answer 1

$\{-20\:;a_{2};a_{3} ;a_{4}; a_{5};a_{6};a_{7};a_{8};12\}$

$a_{1}=-20$

$a_{9}=12$

$a_{9}=a_{1}+8r$

$12=-20+8r$

$12+20=8r$

$8r=32$

$r=32/8$

$r=4$

$PA=>\{-20;-16:-12;-8;-4;0;4;8;12\}$