Question

Interpole quatro meios aritméticos entre -12 e 48.

Answer 1

( -12,__ , ___ , ___ , ___ , 48)

$a_1=-12 \\ a_n=48 \\ n=4+2=6 \\ \\ a_n=a_1+(n-1)r \\ 48=-12+(6-1)r \\ 48=-12+5r \\ 5r=48+12 \\ 5r=60 \\ r=60\div5 \\ r=12$

Logo a P.A será

(-12 , 0 , 12 ,24 , 36 , 48)

Answer 2

Interpole quatro meios aritméticos entre -12 e 48.

n = 2+4 =  6
   
    - 12 + 5r = 48
        5r = 48+12
         5r = 60
           r = 12


 ( - 12,0 , 12, 24, 36 , 48 )