Question

interpole quatro meios aritméticos entre -12 e 48.

Answer 1

$Resolu\c{c}\~ao\to \left[\begin{array}{ccc}-12,?,?,?,?,48\\\\a_n = a_1+(n-1)*r\\\\an=48\\a_1 = -12\\n=6\\r=?\\\\48 = -12+(6-1)*r\\\\48 = -12+5r\\\\5r = 60\\\\\boxed{\boxed{r = 12}}\\\\P.A(-12,0,12,24,36,48)\end{array}\right$

Espero ter ajudado. :))