As funções reais definidas a seguir são bijetoras. Ache a fórmula da inversa f^-1 de cada uma delas:
a)
b)![f(x)= \sqrt[3]{x} -8 f(x)= \sqrt[3]{x} -8](https://tex.z-dn.net/?f=f%28x%29%3D++%5Csqrt%5B3%5D%7Bx%7D+-8)
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A)
B)![f(x) = \sqrt[3]{x} -8\\\\ y = \sqrt[3]{x}-8\\\\ x = \sqrt[3]{y}-8\\\\ \sqrt[3]{y} = x+8\\\\ y = \sqrt[3]{x+8}\\\\ \boxed{f^-(x) = \sqrt[3]{x+8}} f(x) = \sqrt[3]{x} -8\\\\ y = \sqrt[3]{x}-8\\\\ x = \sqrt[3]{y}-8\\\\ \sqrt[3]{y} = x+8\\\\ y = \sqrt[3]{x+8}\\\\ \boxed{f^-(x) = \sqrt[3]{x+8}}](https://tex.z-dn.net/?f=f%28x%29+%3D++%5Csqrt%5B3%5D%7Bx%7D+-8%5C%5C%5C%5C+y+%3D+%5Csqrt%5B3%5D%7Bx%7D-8%5C%5C%5C%5C+x+%3D+%5Csqrt%5B3%5D%7By%7D-8%5C%5C%5C%5C+%5Csqrt%5B3%5D%7By%7D+%3D+x%2B8%5C%5C%5C%5C+y+%3D+%5Csqrt%5B3%5D%7Bx%2B8%7D%5C%5C%5C%5C+%5Cboxed%7Bf%5E-%28x%29+%3D+%5Csqrt%5B3%5D%7Bx%2B8%7D%7D)
B)
Luanferrao:
veja se bateu com o gabarito
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